5x^2-13=-2x^2+36

Solution for 5x^2-13=-2x^2+36 equation:

5x^2-13=-2x^2+36

We move all terms to the left:

5x^2-13-(-2x^2+36)=0

We get rid of parentheses

5x^2+2x^2-36-13=0

We add all the numbers together, and all the variables

7x^2-49=0

a = 7; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·7·(-49)
Δ = 1372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1372}=\sqrt{196*7}=\sqrt{196}*\sqrt{7}=14\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{7}}{2*7}=\frac{0-14\sqrt{7}}{14}
=-\frac{14\sqrt{7}}{14}
=-\sqrt{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{7}}{2*7}=\frac{0+14\sqrt{7}}{14}
=\frac{14\sqrt{7}}{14}
=\sqrt{7}
$